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goblinko [34]
2 years ago
11

What is 8x + 10 ≤ 51 please show work

Mathematics
1 answer:
Vanyuwa [196]2 years ago
3 0

\huge\fbox{Hi~there!~:)}

Let's solve this inequality! :)

Let's start by subtracting 10 from both sides:

\rm{8x\leq 51-10}

\rm{8x\leq 41

Now, divide both sides by 8:

x\leq \displaystyle\frac{41}{8} (Answer)

Decimal form:

\rm{5.125}

I hope you find it helpful.

Feel free to ask if you have any doubts.

\bf{-MistySparkles^**^* here to help

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The length of a rectangle is 1 inch less than twice the width. the area is 21 inches^2 what is the length?
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Formula for area: A = 2l + 2w, where l is the length and w is the width.

Given information:
• l = 2w - 1
• A = 21 in^2

We can plug in our values accordingly and solve for w.

A = 2l + 2w
21 = 2(2w - 1) + 2w
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Plug 3.83 for w into 2w - 1 to find length.

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Finally, check your work by plugging your values into the original equation.

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Answer:
The length is approximately 6.66 inches.
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