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Ludmilka [50]
4 years ago
7

What’s fr the solutions to the quadratic equation 4x^2=64? A. X=16 , -16 B. x=-8, 8 C. x= -4,4 D.x=-2,2

Mathematics
1 answer:
joja [24]4 years ago
4 0

Step-by-step explanation:

Simple

4x2 = 64

Botg are squares so

2x = 8

x = 8/ 2

= 4

Option C is the correct

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Let X be a continuous random variable with density functionf(x)={1−|x|0 for −1
BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

For this case we want to find the density function for Y=X^2

And we have the following density function for the random variable X:

f(X) = 1- |X|,-1 \leq X \leq 1

So we can do this replacing Y=X^2

F_Y (Y \leq y) = P(X^2 \leq y)

If we apply square root on both sides we got:

P(-\sqrt{y} \leq X \leq \sqrt{y}) = \int_{-\sqrt{y}}^0 1+t dt +\int_{0}^{\sqrt{y}} 1-t dt

And if we integrate we got this:

F_Y (y) = [t+ \frac{t^2}{2}] \Big|_{-\sqrt{y}}^0+ [t -\frac{t^2}{2}] \Big|_{0}^{\sqrt{y}}

And replacing we got:

F_Y (y) = [0 -(-\sqrt{y} +\frac{y}{2})] + [\sqrt{y} -\frac{y}{2}]

F_Y (y) = 2 |\sqrt{y}| -y

And if we want to find the density function we just need to derivate the pdf like this:

f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1

3 0
4 years ago
Of 1232 people who came into a blood bank to give blood, 397 people had high blood pressure. Estimate the probability that the n
sweet-ann [11.9K]
I'm going to round these numbers to make them easier to work with. We will get an approximate answer. 
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Answer: 11621.1509596

Hope this helps:) Mark me the brainliest:)

3 0
4 years ago
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AleksandrR [38]

Every line from the tangent to the centre is 90°. This is said in the circle theorems.

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REY [17]

Answer:

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