Area of a circle for (360degrees) = pi*(r^2)
Area of part of a circle with angle θ=(θ/360)*(pi*)*(r^2)
<span>(θ/360)*pi*(6^2)=12*pi
</span>solving, <span>θ=(12/36)*360
</span><span>θ=120 degress
</span>
I am very stuck on this answer simplify 8/12
4.2 is the answer of this question you are asking ✌️
Answer:
n = π/6, π/4, 3π/4, 5π/6
Step-by-step explanation:
sin(3n) − sin n = cos(2n)
Use double and triple angle formulas:
(3 sin n − 4 sin³ n) − sin n = 1 − 2 sin² n
2 sin n − 4 sin³ n = 1 − 2 sin² n
4 sin³ n − 2 sin² n − 2 sin n + 1 = 0
Factor by grouping:
2 sin² n (2 sin n − 1) − (2 sin n − 1) = 0
(2 sin² n − 1) (2 sin n − 1) = 0
Solve:
2 sin² n − 1 = 0
2 sin² n = 1
sin² n = 1/2
sin n = √2/2
n = π/4, 3π/4
2 sin n − 1 = 0
2 sin n = 1
sin n = 1/2
n = π/6, 5π/6
