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4 years ago

8

If it snows tomorrow, then my dentist appointment will be canceled. If my dentist appointment is canceled, then I will clean und

er my bed. Therefore, if it snows tomorrow, then I will clean under my bed. Is this a Law of Detachment?

2 answers:

Dmitry_Shevchenko [17]4 years ago

8 0

Yes this is a Law of Detachment.

scZoUnD [109]4 years ago

7 0

Maybe yes, is a law of detachment

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If the two sides of a triangle are 2 and 7 what is the possible lengths of the third side.

koban [17]

b²=c²-a²

b²=7²-2²

b²=49-4

b²=45

b=√45

b=6.7

3 0

3 years ago

What is the sale price to the nearest cent? $239 television; 10% discount

miv72 [106K]

Answer:

The sale price will be: $215.10

Step-by-step explanation:

We know that:

Sale price = Regular price × (100% - Discount %)

= Regular price × (100% - 10%)

= 239 × 90%

= 239 × 0.9

= 215. 10 $

Therefore, the sale price will be: $215. 10

3 0

3 years ago

a car deceased in value by 25% in the first year. purchased for $28,000, what is the car worth today.

Gwar [14]

Try this: Principal times (1+interest rate as a decimal fraction)^(number of yrs)

In this case, Principal = $28,000; interest rate = -0.25; # of years = 1

So Decrease in value = $28,000 (0.75)^1 = $21,000.

4 0

3 years ago

Johnathan plans on using 2" x 12" boards that cost $2.50 per foot. Assuming he can purchase the exact amount he needs, how much

Kitty [74]

Answer:

$35

Step-by-step explanation:

7 0

3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0

3 years ago