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kolbaska11 [484]
2 years ago
11

Hey! how are y'all? tell me about your day:)

Mathematics
2 answers:
Tamiku [17]2 years ago
8 0

Answer:

Hi, I'm doing good, just bored

nikdorinn [45]2 years ago
4 0
Hey! i’m doing okay , hmm i didn’t do much today’s besides go to school obviously
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(10 POINTS) answer ASAP if you can
Goryan [66]
I think that the answer is R
8 0
3 years ago
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Evaluate this expression.<br> 3^-2
MAVERICK [17]

Answer:Exact Form: one over 9  

1

9

Step-by-step explanation: ,..

4 0
2 years ago
Help me I am bad with percentages
Xelga [282]

Answer:

16.67% less

or

she only made 83% of her anticipated $18,000

Step-by-step explanation:

3000/18000 = 0.1666 or 16.67% less

15000/18000 = 0.8333 or 83%

4 0
2 years ago
Para iniciar un negocio, una pareja pide $5.500.000 para comprar equipo y suministros. Si el préstamo tiene una tasa de 14% de i
Sunny_sXe [5.5K]

Answer:

They will have to pay $5,692,500 in 90 days.

Deben pagar $5,692,500 pagar al final de un período de 90 días.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years..

After t years, the total amount of money is:

T = E + P.

In this question:

P = 5500000, I = 0.14

3 months is 3/12 = 1/4 = 0.25 of an year. So t = 0.25

Then the interest accrued is:

E = P*I*t = 5500000*0.14*0.25 = 192500

What they will have to pay:

T = 192500 + 5500000 = 5692500

They will have to pay $5,692,500 in 90 days.

Deben pagar $5,692,500 pagar al final de un período de 90 días.

7 0
3 years ago
Zane performs the elementary row operation represented by R2-½R1 on matrix A.​
UkoKoshka [18]

Answer:

[2 5 0]

[-7 -11/2 12]

Step-by-step explanation:

We want to perform elementary row operation represented by R2 - ½R1 on matrix A in the figure attached.

Now, matrix A is given as;

[2 5 0]

[-6 -3 12]

Now, R1 is row 1 = [2 5 0]

R2 is row 2 = [-6 -3 12]

Thus, R2 - ½R1 = [-6 -3 12] - ½[2 5 0]

This gives;

[-6 -3 12] - [1 5/2 0] = [-7 -11/2 12]

Now,[-7 -11/2 12] will be the new row 2 since it's just an elementary row operation we did on the Matrix A.

Thus, the new matrix is now;

[2 5 0]

[-7 -11/2 12]

5 0
2 years ago
Read 2 more answers
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