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Inga [223]
3 years ago
13

What are the first four solutions to the sequence: f(1) = 4 and f(n) = 2*f(n-1)+3

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0
F(1) = 4 is given


f(2) = 2*f(2-1)+3
= 2*f(1)+3
= 2*4+3
= 8+3
= 11
f(3) = 2*f(3-1)+3
= 2*f(2)+3
= 2*11+3
= 22+3
= 25
f(4) = 2*f(4-1)+3
= 2*f(3)+3
= 2*25+3
= 50+3
= 53
f(5) = 2*f(5-1)+3
= 2*f(4)+3
= 2*53+3
= 106+3
= 109

f(1) = 4
f(2) = 11
f(3) = 25
f(4) = 53
f(5) = 109
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Step-by-step explanation:

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Now applying  continuity correction we have

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=>    P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )

=>    P(X  >300 ) =  P(Z >  -1.914 )

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    P(Z >  -1.914 ) =  0.97219

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