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lisov135 [29]
3 years ago
9

You are a contractor and charge $45 for a site visit plus an additional $24 per hour for each hour you spend working at the site

. Write and solve an equation to determine how many total hours you have to work to earn $810 working at two separate work sites. Let the number of hours you work be y.
​
Mathematics
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer:

Equation: 810= (90 + 24y)

y = 30 hours

Step-by-step explanation:

Given:

Site visit = $45 per site

cost per hour worked = $24

for <u>each </u>work site, the total amount of money earned

= site visit fee + cost for working

But the question mentions TWO sites, hence there will be two site visits. Therefore for TWO sites, we have to account for TWO site visit fee.

Therefore for TWO sites, the total amount of money earned

= site 1 visit fee + site 2 visit fee + cost for working

= (2 x site visit fee) +  cost for working  ------ Equation 1

We are further given that we worked y hours at the hourly work rate of $24 per hour.

Hence the cost for working

= y hours x hourly rate

= y   x   $24

= $24y   (substituting this into equation 1 above)

for TWO sites, the total amount of money earned

= (2 x site visit fee) +  cost for working

= (2 x $45) +  $24y

= $90 + $24y

= $(90 + 24y)

We are also given that we have to earn $810 for two sites, hence

810 = 90 + 24y    

810 - 90 = 24y

24y = 720

y = 720/24

y = 30 hours

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DerKrebs [107]

Answer:

I'm pretty sure it is d, 5/22

7 0
2 years ago
Please work out and explain​
Mekhanik [1.2K]

Answer:

a = 22

b = 31

c = 13

Step-by-step explanation:

The sum is the same in each row, column, and diagonal.

One of the diagonals is already complete.  The sum is:

16 + 25 + 34 = 75

So the first row adds up to 75:

a + 37 + 16 = 75

a = 22

The second row adds up to 75:

19 + 25 + b = 75

b = 31

And the third row adds up to 75:

34 + c + 28 = 75

c = 13

We can check our answer by finding the sum of each column and the other diagonal.

22 + 19 + 34 = 75

37 + 25 + 13 = 75

16 + 31 + 28 = 75

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3 0
3 years ago
The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 264 feet, f
Digiron [165]

L = 2w - 3

p = 264

2(L + w) = p

2(2w - 3 + w) = 264

2(3w - 3) = 264

6w - 6 = 264

6w = 270

w = 270/6

w = 90/2

w = 45

L = 2w - 3

L = 2(45) - 3

L = 90 - 3

L = 87

The length is 87ft, and the width is 45ft

7 0
2 years ago
Read 2 more answers
The sum of three consecutive even integers is 288288. find the integers.
kirza4 [7]
Suppose the three integers are x, x+2, and x+4
x+x+2+x+4=288
3x+6=288
3x=282
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the three numbers are 94, 96, and 98
4 0
3 years ago
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
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