Question

There are 7 yellow, 6 blue, 9 red, and 3 green ribbons in a drawer. Once a ribbon is selected, it is not replaced. Find each probability.
P(a yellow ribbon and then a blue ribbon)


P(a yellow ribbon and then a blue ribbon)


a. 7/100
b. 42/635
c. 7/120
d. 7/125

Answer 1

Answer:

7/100

Step-by-step explanation:

7 yellow, 6 blue, 9 red, and 3 green ribbons in a drawer

Total ribbons = 25 ribbons

P( yellow) = yellow / total = 7/25

Then not replaced

6 yellow, 6 blue, 9 red, and 3 green ribbons in a drawer

Total ribbons = 24 ribbons

P( blue) = blue / total = 6/24 = 1/4

P(a yellow ribbon and then a blue ribbon) = 7/25 * 1/4 =7/100

Answer 2

Answer:

A: $\frac{7}{100}$

Step-by-step explanation:

There are 25 ribbons total. The probability would be out of the 25 ribbons.

(1):

Yellow: $\frac{7}{25}$

Blue:$\frac{6}{25}$

Red:$\frac{9}{25\\}$

Green:$\frac{3}{25}$

When removing a ribbon that can't be replace, it'll leave you with a total of 24 ribbons.

(2):

Yellow: $\frac{6}{24}=\frac{1}{4}$

Blue: $\frac{5}{24}$

Red:$\frac{8}{24}=\frac{1}{3}$

Green:$\frac{2}{24}=\frac{1}{12}$

Multiply {(1) × (2)}:

Yellow:$\frac{7}{25}$ ×$\frac{6}{24}$ = $\frac{7}{100}$

Blue:$\frac{6}{25}$ × $\frac{5}{24}$ = $\frac{1}{20}$