Answer:

Step-by-step explanation:
To find:
The value of
= ?
Solution:
Kindly consider the equilateral
as attached in the answer area.
Let the side of triangle =
units
Let us draw the perpendicular from vertex A to side BC.
It will divide the side BC in two equal parts.
i.e. BD = DC = 
Using Pythagorean Theorem in
:

Side AD = 
Using Trigonometric ratio:


Putting the values of AD and BD:

Answer:
219m
Step-by-step explanation:
Since the man observes the car with angle 15 before observing in 33 degrees.
For the first observation
The angle observation gives an angle if 33 degrees with the horizontal.
It gives a triangle which I'll attach to the que,
from the first triangle
Tan 33 = 100/y
Y= 100/ tan 33
Y = 153.99m.
This is the distance from the building to the distance where it was secondly observed( 33).
To find x
tan 15 = 100/(153.99+x)
153.99 + x = 100/ tan 15
153.99 + x = 373.21
The distance between the two observed angles
X= 219m.
Answer:
y=x+1
Step-by-step explanation:
First find the slope by subtracting the y values from both points and dividing it by the subtraction of the x values from both points:
-4--2/ -3--1= -2/-2= 1
so the slope is 1
Now find the y-intercept by plugging in the x and y from one of the points into the equation y=x+b
-3=-4+b
1=b
now plug the slope and y intercept in:
y=x+1
hope this helps :D
Answer:
The answer is (d) ⇒ ![pq^{2}r\sqrt[3]{pr^{2}}](https://tex.z-dn.net/?f=pq%5E%7B2%7Dr%5Csqrt%5B3%5D%7Bpr%5E%7B2%7D%7D)
Step-by-step explanation:
* To simplify the cube roots:
If its number then the number must be written in the form x³
then we divide the power by 3 to cancel the radical
If its variable we divide its power by 3 to cancel the radical
∵ ![\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bp%5E%7B4%7Dq%5E%7B6%7Dr%5E%7B5%7D%7D%3Dp%5E%7B%5Cfrac%7B4%7D%7B3%7D%7Dq%5E%7B%5Cfrac%7B6%7D%7B3%7D%7Dr%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%7D)
∴ 
∵ ![p^{\frac{1}{3}}=\sqrt[3]{p}](https://tex.z-dn.net/?f=p%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7Bp%7D)
∵ ![r^{\frac{2}{3}}=\sqrt[3]{r^{2}}](https://tex.z-dn.net/?f=r%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7Br%5E%7B2%7D%7D)
∴ ![p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})](https://tex.z-dn.net/?f=p%28p%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7Dq%5E%7B2%7Dr%28r%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3Dp%28%5Csqrt%5B3%5D%7Bp%7D%29q%5E%7B2%7Dr%28%5Csqrt%5B3%5D%7Br%5E%7B2%7D%7D%29)
∴ ![prq^{2}\sqrt[3]{pr^{2}}}](https://tex.z-dn.net/?f=prq%5E%7B2%7D%5Csqrt%5B3%5D%7Bpr%5E%7B2%7D%7D%7D)
∴ The answer is (d)