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Ugo [173]
3 years ago
7

I did the first of one

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

2) 7, 14, 21, 28, 35, 42, 49, 56, 63, 70

3) 20, 18, 16, 14, 12, 10, 8, 6, 4, 2

4) 6, 11, 16, 21, 26, 31, 36, 41, 46, 51

5) 10, 20, 30, 40, 50, 60, 70, 80, 90, 100

6) 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

7) 9, 18, 27, 36, 45, 54, 63, 72, 81, 90

8) 16, 18, 20, 22, 24, 26, 28, 30, 32, 34

9) 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

10) 8, 16, 24, 32, 40, 48, 56, 64, 72, 80

11) 11, 13, 15, 17, 19, 21, 23, 25, 27, 29

12) 12, 14, 16, 18, 20, 22, 24, 26, 28, 30

Step-by-step explanation:

Add 7 on the first one, subtract 2 on the second, add 5 on the fourth, add 10 on the fifth, add 6 on the sixth, add 9 on the seventh, add 2 on the eighth, add 9 on the ninth, add 8 on the tenth, add 2 on the eleventh, and add 2 on the twelfth.


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3 years ago
one interior angle of a polygon is equal to 800 and each of the other interior angles are 128 degrees. Find the number of sides
KiRa [710]

Answer:

6

Step-by-step explanation:

Given information:

Interior angle of a polygon cannot be more that 180°.

One interior angle = 80^{\circ}

Other interior angles are  = 128^{\circ}

Let n be the number of sides of the polygon.​

Sum of interior angles is

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Sum=80+128n-128

Combine like terms.

Sum=128n-48           .... (1)

If a polygon have n sides then the sum of interior angles is

Sum=(n-2)180

Sum=180n-360           .... (2)

Equating (1) and (2) we get

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Isolate variable terms.

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Divide both sides by 52.

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3 years ago
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144=9x

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Ur welcome :)

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Answer:

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Step-by-step explanation:

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