Find the Slope -6,7 -10,10
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Answer:
<em>The calculated t- value = 1.11 > 2.89 at 0.025 level of significance</em>
<em>Null hypothesis is rejected </em>
<em>The engineer designed the valve such that it would produce a mean pressure is not equal to 5.4</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given mean of the Population (μ) = 5.4</em>
<em>Given sample size 'n' = 9</em>
<em>Mean of the sample (x⁻) = 5.7</em>
<em>Standard deviation of the sample (s) = 0.81</em>
<u><em>Step(ii):-</em></u>
<em>Null Hypothesis: H₀:</em> The engineer designed the valve such that it would produce a mean pressure of 5.4
H₀: μ = 5.4
<em>Alternative Hypothesis : H₁:</em> μ ≠ 5.4
Level of significance = 0.025
Test statistic
t = 1.11
<em>Degrees of freedom </em>
<em>ν = n-1 = 9-1 =8</em>
t₀.₀₁₅ , ₈ = 2.89
<em>The calculated t- value = 1.11 > 2.89 at 0.025 level of significance</em>
<em>Null hypothesis is rejected </em>
<em>The engineer designed the valve such that it would produce a mean pressure is not equal to 5.4</em>
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Answer:
Check Explanation
Step-by-step explanation:
The map isn't available, but, one can draw this bearings with the descriptions given
Angles for bearings are usually drawn, reading from the north direction.
A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.
For the sketch on the map.
On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.
Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.
Wherever the line from the hospital meets the line from the stadium, is where the University is located.
Hope this Helps!!!!
The probability that a normally distributed data with a mean of μ and a standard deviation of σ is less than a value x is given by:
Given that μ = 16.5 and σ = 0.804984 and that the probability that the <span>mean oil-change time being at or below the sample mean for which there is an area of 0.10 to the left under the normal curve, then:
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Given that μ = 16.5 and σ = 0.804984 and that the probability that the <span>mean oil-change time being at or below the sample mean for which there is an area of 0.10 to the left under the normal curve, then: