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4 years ago

John flips 10 coins and lays them out in a straight line.

Mathematics

1 answer:

belka [17]4 years ago

3 0

For every coin, two options are possible. The formula for calculting all possibilities is $p^{t}$ where p is possibilities per time and t is times.

Therefore, there are $2^{10}$ which is 1024 combinations.

The formula for calculating probability is $\frac{w}{t}$ where w is the ways to achieve the desired outcome, and t is the total outcomes possible.

Therefore, there is a $\frac{1}{1024}$ chance of flipping ten tails.

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Kendra charges $11 to shovel a driveway. She shoveled 4 driveways on Saturday and then some more on Sunday. She made $143 for th

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4 years ago

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3 years ago

A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$

Plug in n = 12 and r = 9

$=\frac{12!}{9!\left(12-9\right)!}$

$=\frac{12!}{9!\cdot \:3!}$

$=\frac{12\cdot \:11\cdot \:10}{3!}$ ∵ $\frac{12!}{9!}=12\cdot \:11\cdot \:10$

$=\frac{1320}{6}$ ∵ $3!\:=\:3\times 2\times 1=6$

$=220$

Thus, the probability will be:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$=\frac{220}{4096}$

$=\frac{55}{1024}$

Thus, the probability of the coin landing tails up exactly nine times will be:

$P\left(E\right)=\frac{55}{1024}$

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3 years ago