See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
Answer:
8² = 4² + 5² - 2(4)(5) cos(P)
which is the third option
Explanation:
The general rule of cosine is:
a² = b² + c² - 2bc*cos(A)
In our triangle:
a is substituted by p = 8 cm
b is substituted by n = 4 cm
c is substituted by m = 5 cm
A is substituted by P which we want to find
Replace the variables in the general equation with the givens as follows:
p² = n² + m² - 2mn*cos(P)
8² = 4² + 5² - 2(4)(5) cos(P)
Hope this helps :)
Answer:
last payment is 45% and is $225
Step-by-step explanation:
Answer:
See below ~
Step-by-step explanation:
<u>Question 1</u>
<u>The missing angles</u>
- Both the unknown angles have the same value as the other two angles in the triangles are the same
- ∠(missing) = 180 - (72 x 2)
- ∠(missing) = 180 - 144
- ∠(missing) = 36°
⇒ The sides are <u>equal</u>
⇒ Angles are <u>not 90°</u>
⇒ It is a <u>rhombus</u>
<u></u>
<u>Question 2</u>
- The <u>diagonals</u> of the shape <u>bisect other</u> (Statement 1)
- NY = NW (given)
- XN = NZ (given)
- ∠XNY = ∠WXZ (vertically opposite angles)
- ΔXNY ≅ ΔWXZ (SAS)
- They form <u>two congruent triangles</u> (Statement 2)
- From these two statements, it is evident the figure is a <u>parallelogram</u>