Answer:
10.98 days is 10.98/3.66 = 3 half life periods and half of the mass is lost at each half life. You can do this in your head. I have!!
Step-by-step explanation:
The third one, 40-45 because the difference of the rest are 4, while that one is 5.
The thief originally stole 64 plants.
<h3>What is arithmetic?</h3>
In mathematics, it deals with numbers of operations according to the statements.
Here,
Let the number of plants originally stolen by the thief be x.
On the way out, the thief meets three security guards, one after another. To each security guard, the thief is forced to give one-half of the plants that he still had, plus 2 more.
Here,
For gourd 1 the planet is given = 1/2 x
For gourd 2 the planet is given = 1/2 * 1/2 x = 1/4 x
For gourd 3 the planet is given = 1/2*1/4 x = 1/8 x
Total plant given to the gourds = 1/2x +1/4x +1/8x + 2 = 7/x/8x +2
Finally, the thief leaves the nursery with 10 plants
x - 7x/8 + 2 = 10
x/8 = 8
x = 64
Thus, the thief stole 64 plants.
Learn more about arithmetic here:
brainly.com/question/14753192
<h3>
#SPJ1</h3>
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
We are told that 21% of the total cans is 63 cans, therefore
100% of all the cans collected would be.
(63*100)/21=300 cans were collected in all
