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salantis [7]
3 years ago
11

What are the factors of 83?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
8 0

83 is a prime number.

Prime factorization: 83 is prime.

The exponent of prime number 83 is 1. Adding 1 to that exponent we get (1 + 1) = 2. Therefore 83 has exactly 2 factors.

Factors of 83: 1, 83

Factor pairs: 83 = 1 x 83

83 has no square factors that allow its square root to be simplified. √83 ≈ 9.11043

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Answer:

The equation which can be used to find the value of numbers

(x) + (x + 1) + (x + 2) = - 21

Step-by-step explanation:

Let the first no. is =  x

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Given that Three consecutive integers have a sum of –21.

Therefore

(x) + (x + 1) + (x + 2) = - 21

This is the equation which can be used to find the value of numbers.

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Factorize 2a^2+7a-15​
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\huge\bf  \pink {\underline{Solution :-}}

2 {a}^{2}  + 7a - 15

= 2 {a}^{2}  + 10a - 3a - 15

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\\

\bf \purple{ \underline{ Important  \: Formulas  \: for  \: Factorization :-}}

• \:  {a}^{2}  + 2ab + {b}^{2} =  {(a + b)}^{2}

• \: (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

• \:  {a}^{2} - 2 ab  +  {b}^{2}  =  {(a - b)}^{2}

• \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3} =  {(a + b)}^{3}

• \:  {a}^{3}   -  3 {a}^{2} b + 3a {b}^{2}   -  {b}^{3} =  {(a  - b)}^{3}

•  \:  {(a + b)}^{2}  +  {(a - b)}^{2}  = 2( {a}^{2}  +  {b}^{2} )

• \: {(a + b)}^{2}   -   {(a - b)}^{2}  = 4ab

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• \: (a  -  b)( {a}^{2}    + ab   +  {b}^{2}  ) =  {a}^{3}   -  {b}^{3}

• \:   {( \frac{a + b}{2} )}^{2}  - ( {\frac{a - b}{2} } )^{2}  = ab

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