Answer:
The area of triangle is ![8 \frac{1}{3}\ m^{2}](https://tex.z-dn.net/?f=8%20%5Cfrac%7B1%7D%7B3%7D%5C%20m%5E%7B2%7D)
Step-by-step explanation:
we know that
The area of a triangle is equal to
A=(1/2)bh
we have
b=8 1/3 m
convert to an improper fraction
8 1/3 m=(8*3+1)/3=25/3 m
The fourth root of 16 is equal to 2
![\sqrt[4]{16}=(2^{4})^{1/4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%282%5E%7B4%7D%29%5E%7B1%2F4%7D%3D2)
so
h=2 m
substitute
![A=(1/2)(25/3)2=25/3\ m^{2}](https://tex.z-dn.net/?f=A%3D%281%2F2%29%2825%2F3%292%3D25%2F3%5C%20m%5E%7B2%7D)
convert to mixed number
![25/3=(24/3)+(1/3)=8+1/3=8 \frac{1}{3}\ m^{2}](https://tex.z-dn.net/?f=25%2F3%3D%2824%2F3%29%2B%281%2F3%29%3D8%2B1%2F3%3D8%20%5Cfrac%7B1%7D%7B3%7D%5C%20m%5E%7B2%7D)
Answer:2.3 0,8 40.3
Step-by-step explanation:
You need to write the entire function: y = f(x) = 2x + 6.
Here the input quantity is x, and the output is y (or f(x)).
1 + .3 +.07+.005 x 10 - 6
The maximum height is yo<span> = 0</span>
When the projectile is at its maximum height <span> v</span>y = 0.
Note that the maximum height is determined solely by the initial velocity in the y direction and the acceleration due to gravity. :)