☃ Solve:
☃ Multiply 2 on both sides.
☃ Y>--12
Use pemdas, and start with parentheses 9 + 8 is 17. Multiply the 2 sides. 17 times 2 is 34 and 6 times 14 is 84. Now subtract 84 from 34 and get 50
No, the coordinates doesn’t make the equation a true statement, therefore it can’t be a solution.
2(x+11) is equivalent to 3x+10x+12
Answer:
C x=6
Step-by-step explanation:
sqrt(x+3) = x-3
Square each side
(sqrt(x+3))^2 = (x-3)^2
x+3 = (x-3)^2
x+3 = (x-3)(x-3)
FOIL
x+3 = x^2 -3x-3x+9
Combine like terms
x+3 = x^2 -6x+9
Subtract x from each side
x-x+3 = x^2 -6x-x +9
3 = x^2 -7x +9
Subtract 3 from each side
3-3 = x^2 -7x +9-3
0 = x^2 -7x+6
Factor
0 = (x-6)(x-1)
Using the zero product property
x-6=0 x-1 =0
x=6 x=1
Since we squared we need to check for extraneous solutions
x=1
sqrt(1+3) = 1-3
sqrt(4) = -2
2=-2
False
Extraneous
x=6
sqrt(6+3) = 6-3
sqrt(9) = 3
3=3
True solutions
