I think that it us C but do not take my word for it.
The answer is y = -5x/2 + 5
<span>70=2(x+x-9)
</span><span>2x-9=35
x=22
</span><span>length 22, width 13</span>
The product of the slopes of the perpendicular lines must equal -1. Let the unknown slope be m.
(5/4)m = -1
m = -(4/5)
The required equation is of the form:
y = -(4/5)x + b
Plugging in the coordinates of the given point, we get:
5 = -(16/5) + b
b = 8 1/5.
The required equation is therefore:
y = -(4/5)x + 8 1/5
x = ± i
rearrange the equation and equate to zero
2x² - 6x = - 5 ⇒ 2x² - 6x + 5 = 0
this doesn't factor with integers, hence use the quadratic formula to solve
with a = 2, b = - 6 and c = 5
x = (6 ± √(36 - 40 ) )/4
= (6 ± √(-4) ) / 4
= (6 ± 2i ) / 4
x = ± i