Answer:
x < -3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
9(2x + 1) < 9x - 18
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 9: 18x + 9 < 9x - 18
- Isolate <em>x</em> terms: 9x + 9 < -18
- Isolate <em>x</em> term: 9x < -27
- Isolate <em>x</em>: x < -3
Here we see any value <em>x</em> smaller than -3 would work as a solution to the inequality.
Answer:
q = -3/8
Step-by-step explanation:
Clearing out the fractions first simplifies this problem. The LCD here is 8, so we multiply all three terms of 7/8 = q + 1/2 by 8 and simplify the result:
7 + 8q = 4.
Combining the constants, we get: 8q = 4 - 7, or 8q = -3.
Finally, solve for q:
q = -3/8
4/33
the way i do it, is i want 12 to be recurring, so i do 12/100, then i take away one from the denominator, so i get 12/99 = 0.121212.....
similarly, if i wanted 0.123123123,
i could do 123/1000 then take away one from the denominator to get 123/999 and that should give us 0.123123123123
Answer:
i think it would be adding like terms
Step-by-step explanation:
i only say this because the first step you would do is (4x-7) because of the () but you cant because they arent like terms.....
but just try adding the like terms, but im not completely sure if thats what you do (thats the best i got )