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amid [387]
3 years ago
8

Evaluate 4 49 × 7 13

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

320137

Step-by-step explanation:

i used a calculator

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Find the degree of the polynomial<br> 2x^4y^2+9x^2y^5-3x^4y^4
coldgirl [10]

Answer:

the polynomial has degree 8

Step-by-step explanation:

Recall that the degree of a polynomial is given by the degree of its leading term (the term with largest degree). Recall as well that the degree of a term is the maximum number of variables that appear in it.

So, let's examine each of the terms in the given polynomial, and count the number of variables they contain to find their individual degrees. then pick the one with maximum degree, and that its degree would give the actual degree of the entire polynomial.

1) term  2\,x^4\,y^2  contains four variables "x" and two variables "y", so a total of six. Then its degree is: 6

2) term  9\,x^2\,y^5  contains two variables "x" and five variables "y", so a total of seven. Then its degree is: 7

3) term  -3\,x^4\,y^4  contains four variables "x" and four variables "y", so a total of eight. Then its degree is: 8

This last term is therefore the leading term of the polynomial (the term with largest degree) and the one that gives the degree to the entire polynomial.

8 0
4 years ago
Read 2 more answers
What is the GCF of 2+18+40
vlabodo [156]
2 is the GCF of <span>2+18+40
.</span>
6 0
3 years ago
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Don't answer this...<br>I made a mistake...
Sveta_85 [38]

Answer: don’t mind me ima just type ggyuuffnfhhfhc

Step-by-step explanation:

KBuhdhhdh

5 0
3 years ago
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PLEASE HELPPPP Prove That: 5^31–52^9 is divisible by 100. do it like _____*100
Andru [333]

Answer:

5^31

Step-by-step explanation:

10052^9

This should be correct

8 0
3 years ago
Use integration by parts to find the integrals in Exercise.<br> ∫(x+6)ex dx.
skelet666 [1.2K]

Answer:

xe^x+5e^x

Step-by-step explanation:

We have given integral \int (x+6)e^xdx

\int (xe^x+6e^x)dx

\int (I_1+I_2)dx , here I_1=xe^x and I_2=6e^x

Now first integrate I_1

So I_1=\int xe^x

Integrating by part

I_1=x\int e^x-\int e^x\frac{d}{dx}x

I_1=x e^x- e^x

I_2=6\int e^x=6e^x

So I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x

5 0
3 years ago
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