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sukhopar [10]
3 years ago
7

The area of Maxine's living room is 88 square feet. The length of the room is 3 feet longer than the width. Which quadratic equa

tion can Maxine use to determine the width, x, of her living room?

Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

B. Because x(x+3) is x^2+3x

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Please explain the answer​
Phantasy [73]

Answer:

  yes

Step-by-step explanation:

The side lengths satisfy the Pythagorean theorem, so the triangle is a right triangle.

  7.5² +10² = 12.5²

  56.25 +100 = 156.25

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You may recognize that the ratios of side lengths are ...

  7.5 : 10 : 12.5 = 3 : 4 : 5

A 3-4-5 triangle is a well-known right triangle, as this is the smallest set of integers that satisfy the Pythagorean theorem. They also happen to be consecutive integers, so form an arithmetic sequence. Any arithmetic sequence that satisfies the Pythagorean theorem will have these ratios.

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If you're familiar with trigonometry, you know the law of cosines tells you ...

  c² = a² + b² - 2ab·cos(θ) . . . . where θ is the angle between sides a and b. This reduces to the Pythagorean theorem when θ=90°, which makes cos(θ)=0. If the sides do not satisfy the Pythagorean theorem, cos(θ)≠0 and the triangle is not a right triangle.

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3 years ago
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Zina [86]

Answer:

29520728184915396206153835295

3 0
3 years ago
A group of friends were working on a student film that had a budget of $600. They used $198 of their budget on props. What perce
uranmaximum [27]
Pretty sure it is 33% because 198/600 is 33.
3 0
2 years ago
Carmen cuts a 60-inch-long wire into pieces that are 3/4 inch long.How many pieces does she have?
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Since we have to divide 60 by ¾, so get 60/ ¾ =60* 4/3 = 80
7 0
3 years ago
Read 2 more answers
"Solving Equations by Completing the Square: m^2+2m-48=-6
kvv77 [185]
m^2+2m-48=-6 \\ \\ m^2+2m-48+6=0\\ \\m^2+2m-42=0\\ \\a=1, \ b= 2, \ c= -42 \\ \\\Delta = b^{2}-4ac = 2^{2}-4*1*(-42)= 4+168 =172 \\\\\sqrt{\Delta }=\sqrt{172} =\sqrt{4*43}=2\sqrt{43}\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-2-2\sqrt{43}}{2}=\frac{2(-1-\sqrt{43})}{2}= -1-\sqrt{43} \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} = \frac{-2+2\sqrt{43}}{2}=\frac{ 2(-1+\sqrt{43})}{2}= -1+\sqrt{43}
5 0
3 years ago
Read 2 more answers
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