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pogonyaev
3 years ago
8

A coordinate plane with a line passing through (negative 4, 3), (0, 1), and (4, negative 1). Which linear function is represente

d by the graph? f(x) = –2x + 1 f(x) = –f(x) equals negative StartFraction one-half EndFraction x plus 1.x + 1 f(x) = f(x) equals StartFraction one-half EndFraction x plus 1.x + 1 f(x) = 2x + 1
Mathematics
2 answers:
tester [92]3 years ago
9 0

Answer:

(its B)    f(x) = –f(x) equals negative StartFraction one-half EndFraction x plus 1.x + 1

Step-by-step explanation:

9966 [12]3 years ago
8 0

Answer:

Step-by-step explanation:

If these 3 points are collinear, then we can find the slope of the linear function using any 2 of those points.  Suppose we use (-4, 3) and (0, 1):  

As we move from (-4, 3) to (0, 1), x increases by 4 and y decreases by 2.  Hence, the slope of this lilne is m  = rise/run = -2/4, or m = -1/2.

Using the slope-intercept formula y = mx + b and replacing y with 1, x with 0 and m with -1/2, we get:

1 = (-1/2)(0) + b, or b = 1.  Then the desired equation is y = f(x) = (-1/2)x + 1

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Answer:

21

Step-by-step explanation:

The denominators are 3 and 7 and those are both odd numbers.

You can not get a number lower than 21. Therefore 21 is the LCM (Lowest common denominator.)  

Hope this helps :)

5 0
3 years ago
How do you determine where f(x)=cos^(-1)(lnx) is continuous?
olga nikolaevna [1]
\ln x is continuous over its domain, all real x>0.

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If y=\ln x, then we have -1\le \ln x\le1\implies \dfrac1e\le x\le e as the domain of \cos^{-1}(\ln x).

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6 0
3 years ago
The residual plot for a data set is shown.
Cerrena [4.2K]

Answer:

The regression line is not a good model because there is a pattern in the residual plot.

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Given is a  residual plot for a data set

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3 0
3 years ago
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Help with this math question
tresset_1 [31]
The given inequality is:

|-8x+24| \leq 16

This inequality can be divided in two parts as:

a) -16 \leq -8x +24
b) -8x + 24 \leq 16

Solving part a:

-16 \leq -8x+24 \\  \\ &#10;-40 \leq -8x \\  \\ &#10;5 \geq x \\ &#10;or \\ &#10;x \leq 5

Solving part b:

-8x+24 \leq 16 \\  \\ &#10;-8x \leq -8 \\  \\ &#10;x \geq 1

Therefore, the solution to the given inequality is x \leq 5 and x \geq 1. Combining both the ranges we get the solution: 1 \leq x \leq 5.

In interval notation, this solution can be expressed as [1,5]
3 0
4 years ago
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