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3 years ago

WILL MARK BRAINLIEST! Match each pair of angles with the correct angle relationship(s). Explain your reasoning for each.

Mathematics

1 answer:

Ann [662]3 years ago

4 0

Answer:

∠AOB and ∠COD are vertical angles

∠DOE and ∠COD are complementary, adjacent

∠AOB and ∠AOD are supplementary, adjacent.

Step-by-step explanation:

Let's start with ∠AOB and ∠COD.

Looking at this, we can see they are the same angles formed by two lines that intersected. These are vertical angles as they are opposite each other.

∠DOE and ∠COD together form the angle ∠EOC, which is a right angle. Complementary angles are any of two that add up to 90°, so these two angles are complementary. They are also adjacent because they are right next to each other.

∠AOB and ∠AOD together form the angle ∠BOD, which has a measure of 180°. Supplementary angles are any of two that add up to 180°, so ∠AOB and ∠AOD are supplementary. They are also adjacent as they are touching/right next to each other.

I hope this helped!

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ExtremeBDS [4]

Answer:

3:10

Step-by-step explanation:

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3 years ago

The auto parts department of an automotive dealership sends out a mean of 4.34.3 special orders daily. What is the probability t

Svetlanka [38]

Answer:

$P(X = 5) = 0.166$

Step-by-step explanation:

Given

$Mean = 4.3$

$x = 5$

Required

Determine the probability that the order is 5

This question can be answered using Poisson distribution.

$P(X = x) = \frac{\alpha ^x e^{-\alpha}}{x!}$

Where

$\alpha$ is used to represent the mean

and

$\alpha = 4.3$

$x = 5$

$e = 2.71828$ ---- Euler's constant

So, we have:

$P(X = x) = \frac{\alpha ^x e^{-\alpha}}{x!}$

$P(X = 5) = \frac{4.3^5 * 2.71828^{-4.3}}{5!}$

$P(X = 5) = \frac{4.3^5 * 2.71828^{-4.3}}{5* 4 * 3 * 2 *1}$

$P(X = 5) = \frac{4.3^5 * 2.71828^{-4.3}}{120}$

$P(X = 5) = \frac{1470.08443 * 0.01356859825}{120}$

$P(X = 5) = \frac{19.9469850243}{120}$

$P(X = 5) = 0.1662248752$

$P(X = 5) = 0.166$ Approximated

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3 years ago

wilma buys a new game that is priced $43.89. she gets successive discounts of 15% followed by 5% off on the game. the purchase p

castortr0y [4]

If you would like to know the purchase price of Wilma's game, you can calculate this using the following steps:

15% of $43.89 = 15% * 43.89 = 15/100 * 43.89 = $6.5835 = $6.58

$43.89 - $6.58 = $37.31

5% of $37.31 = 5% * 37.31 = 5/100 * 37.31 = $1.8655 = $1.87

$37.31 - $1.87 = $35.44

The correct result would be $35.44.

5 0

3 years ago

Read 2 more answers

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$