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3 years ago

14

evaluate if a = 3 b =4 and C=12 cuz there's more to the question there's more to the question will Mark brainiest if you can ans

wer this take a look at the picture and show your work please

2 answers:

Natasha_Volkova [10]3 years ago

8 0

2(3^2) + 4^3 - 12
2(9) + 64 - 12
18 + 52 = 70
70 is your answer (:

tia_tia [17]3 years ago

6 0

2(3)^2+(4)^3-12
2(9)+ 64-12
18+52
70

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solniwko [45]

The answer is 0.89 pounds of fruit per serving- please give brainliest answer!

5 0

3 years ago

Fill in the table using this function rule y=5x-3

Rudiy27

Answer:

-2, -13

0, -3

2, 7

4, 17

Step-by-step explanation:

To fill out the table, substitute the table x-values into the equation and the y-values will fill the table.

y = 5x - 3

y = 5(-2) - 3

y = -10 - 3

y = -13

This means the table value corresponding to -2 should be -13.

y = 5x - 3

y = 5(0) - 3

y = 0 - 3

y = -3

This means the table value corresponding to 0 should be -3.

y = 5x - 3

y = 5(2) - 3

y = 10 - 3

y = 7

This means the table value corresponding to 2 should be 7.

y = 5x - 3

y = 5(4) - 3

y = 20 - 3

y = 17

This means the table value corresponding to 4 should be 17.

6 0

3 years ago

help PLZ help me with the work on the picture I need to give it in tommorow I don't know how to do it ;-;

jok3333 [9.3K]

1a) 25/100 so 1/4
1b) 7 billion times .25 is 1,750,000,000
2) 17 divided by 8 is 2.125 times more

3 0

3 years ago

In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa

marissa [1.9K]

Answer:

The <em>95% confidence interval</em> for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The <em>confidence interval</em> of the mean is given by the next formula:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$ [1]

We already know (according to the U.S. Department of Justice):

The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years ( $\\ \sigma = 9.6$ years).
The number of observations for the sample taken is $\\ n = 32$ .
The sample mean, $\\ \overline{x} = 38.9$ years.

For $\\ z_{1-\frac{\alpha}{2}}$ , we have that $\\ \alpha = 0.05$ . That is, the <em>level of significance</em> $\\ \alpha$ is 1 - 0.95 = 0.05. In this case, then, we have that the <em>z-score</em> corresponding to this case is:

$\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}$

Consulting a cumulative <em>standard normal table</em>, available on the Internet or in Statistics books, to find the z-score associated to the probability of, $\\ P(z$ , we have that $\\ z = 1.96$ .

Notice that we supposed that the sample is from a population that follows a <em>normal distribution</em>. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, $\\ \mu$ , and standard deviation, $\\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}$ .

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

That is, we have:

$\\ \overline{x} = 38.9$ years.

$\\ z_{1-\frac{\alpha}{2}} = 1.96$

$\\ \sigma = 9.6$ years.

$\\ n = 32$

Then

$\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}$

$\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}$

$\\ 38.9 \pm 1.96*1.697056$

$\\ 38.9 \pm 3.326229$

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

$\\ 38.9 + 3.326229$

$\\ 42.226229 \approx 42.23$ years.

Lower limit:

$\\ 38.9 - 3.326229$

$\\ 35.573771 \approx 35.57$ years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0

3 years ago

Fifty five miles per hour converted to feet per second

stiks02 [169]

$\frac{55miles}{hour}*\frac{hour}{3600 seconds}*\frac{5280feet}{mile}$
$\frac{55}{1}*\frac{1}{3600 seconds}*\frac{5280feet}{1}=80.67ft/sec$

6 0

3 years ago