Question

Which of the following could be the equation for a parabola that opens to the

Answer 1

Answer:

D. $x=-(y+12)^2+5$

Step-by-step explanation:

A parabola that opens to the left has the equation

$(y-y_0)^2=-2p(x-x_0),$

where $(x_0,y_0)$ is the vertex.

If the vertex of the parabola is at the point (5,-12), then its equation is

$(y-(-12))^2=-2p(x-5)\\ \\(y+12)^2=-2p(x-5)$

When $p=\frac{1}{2},$ the equation is

$(y+12)^2=-(x-5)\\ \\(y+12)^2=-x+5\\ \\x=-(y+12)^2+5$