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2 years ago

I will mark brainliest

Mathematics

1 answer:

uranmaximum [27]2 years ago

3 0

To start off, simplify the equation if needed:
3m>=21
Since both sides are divisible by 3, you can simplify for the equation to be

m>=7

Next is to find the domain of the line graph. Since the sign is more than or equal to (>=), the circle is closed.
And since m is MORE THAN OR EQUAL TO, the section starts at 7 (closed circle), and continues after. Therefore, your answer will be the third selection.

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HELP ME PLS THIS IS TIMED OMG LMFJAHAH

Delicious77 [7]

Step-by-step explanation:

I think its Domain: -2,-1,3,-5,-8

Range:5,-2,5,-2,-2

4 0

2 years ago

What are the first 10 digits after the decimal point when the fraction $\frac17$ is written in base 16?

Virty [35]

Answer:

The amswer is "2,4,9....."

Step-by-step explanation:

$x=\frac{1}{7}\\\\x_d=0.\overline{142857}\\\\x_h=0.\overline{249}\\\\$

by leave you to work out the other 7 digits:

$\to \frac{1}{7}\approx \frac{a}{16}\\\\a= \text{first hex digit}\\\\a=floor(\frac{16}{7})=2\\\\$

$\to \frac{1}{7}- \frac{a}{16}\approx \frac{b}{16^2}\\\\b= \text{second hex digit}\\\\b=floor(\frac{16^2}{7} -16a)=4\\\\$

$\to \frac{1}{7}- \frac{a}{16}-\frac{b}{16^2} \approx \frac{c}{16^3}\\\\c= \text{third hex digit}\\\\c=floor(\frac{16^3}{7} -16^2a-16b)=9\\\\$

8 0

2 years ago

Suppose that the augmented matrix for a linear system has been reduced by row operations to the given row echelon form. Solve th

erastovalidia [21]

Answer:

a) x = -37 , y = -8, z = 5.

b) w = 13z-10, x = 13z-5, y= 2-z, z = free parameter.

c) v = 2z-7w-11, w = free parameter, x = -3z-4, y = 9-3z, z = free parameter

d) No solution

Step-by-step explanation:

a) $\left[\begin{array}{cccc}1&-3&4&7\\0&1&2&2\\0&0&1&5\end{array}\right]$

The following set of equations are:

z = 5

y+2z=2

x-3y+4z=7

Solving above equations:

y = -8, x = 7-4(5)+3(-8) = -37

b) $\left[\begin{array}{ccccc}1&0&8&-5&6\\0&1&4&-9&3\\0&0&1&1&2\end{array}\right]$

The following set of equations are:

y+z = 2

x+4y-9z=3

w+8y-5z=6

Solving above equations:

z = free parameter - No. of columns > No. of rows; hence, multiple solutions.

y = 2-z, x = 3+9z-4(2-z) = -5+13z, w = 6+5z-8(2-z) = 13z-10

c) $\left[\begin{array}{cccccc}1&7&-2&0&-8&-3\\0&0&1&1&6&5\\0&0&0&1&3&9\end{array}\right]$

The following set of equations are:

y + 3z = 9

x + y + 6z = 5

v + 7w -2x -8z = -3

Solving above equations:

z & w = free parameter - No. of columns > No. of rows; hence, multiple solutions.

y = 9-3z, x = -3z-4, v = -11+2z-7w

d) $\left[\begin{array}{cccc}1&-3&7&1\\0&1&4&0\\0&0&0&1\end{array}\right]$

The following set of equations are:

0 = 1

y + 4z = 0

x-3y+7z = 1

Solving above equations:

No Solution as the first equation is inconsistent

5 0

2 years ago

Need help thanks don’t understand

kykrilka [37]

Answer:

You need help with what-?

7 0

2 years ago

Which answer? I'm stuck, please help

andriy [413]

It would be the second one.
4(2x^2 + 5y^2)(2x^2 - 5y^2)

7 0

2 years ago

Read 2 more answers