(5,-3) (-1,6)
y=mx+b
calculate m:
(-3-6)/(5-(-1)
=-9/6=-1.5
y=-1.5x+b
insert the (5, -3) point to calculate b:
-3=-1.5*5+b
-3=-7.5+b
4.5=b
b=the y intercept, so the line intercepts x=0 at y=4.5
After, thorough research I believe that there are 265 pine trees and 0 elm trees since decidous and semi-decidous do not grow near conifers.
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Answer:
y = 3/4x + 3
Step-by-step explanation:
Please mark me brainliest. Please I have never
been marked brainliest before.
1. x greater than or equal to 4 (B)
2. x does not equal 4 (C)
3. A
4. B
5. B
6. A
7. B
8. C
(The pictures were out of order but i did it by number shown in the pictures. Hope this helps.)
