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bazaltina [42]
3 years ago
6

The Lucas numbers are defined by the recursive formula t1 = 2, t2 = 1, tn = tn - 1 + tn - 2, where n âN and n > 2. What are t

he first 9 Lucas numbers?
Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

The first two are given to you, t_1=2 and t_2=1. Use the recursive formula to get the 3rd term; then use the 2nd and 3rd terms to get the 4th; and so on.

Since the <em>n</em>-th Lucas number is the sum of the previous two Lucas numbers, you have

t_3 = t_2 + t_1 = 1 + 2 = 3

t_4 = t_3 + t_2 = 1 + 3 = 4

t_5 = t_4 + t_3 = 4 + 3 = 7

t_6 = t_5 + t_4 = 7 + 4 = 11

t_7 = t_6 + t_5 = 11 + 7 = 18

t_8 = t_7 + t_6 = 18 + 11 = 29

t_9 = t_8 + t_7 = 29 + 18 = 47

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