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2 years ago

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The Lucas numbers are defined by the recursive formula t1 = 2, t2 = 1, tn = tn - 1 + tn - 2, where n âN and n > 2. What are t

he first 9 Lucas numbers?

1 answer:

Lapatulllka [165]2 years ago

3 0

The first two are given to you, $t_1=2$ and $t_2=1$ . Use the recursive formula to get the 3rd term; then use the 2nd and 3rd terms to get the 4th; and so on.

Since the <em>n</em>-th Lucas number is the sum of the previous two Lucas numbers, you have

$t_3 = t_2 + t_1 = 1 + 2 = 3$

$t_4 = t_3 + t_2 = 1 + 3 = 4$

$t_5 = t_4 + t_3 = 4 + 3 = 7$

$t_6 = t_5 + t_4 = 7 + 4 = 11$

$t_7 = t_6 + t_5 = 11 + 7 = 18$

$t_8 = t_7 + t_6 = 18 + 11 = 29$

$t_9 = t_8 + t_7 = 29 + 18 = 47$

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Drag the tiles to the correct boxes to complete the pairs.

Ne4ueva [31]

Answer:

Part 1) $-1.25$ -------> $2.75/(-2.2)$

Part 2) $-4\frac{1}{3}$ --------> $(-2\frac{3}{5}) / (\frac{3}{5})$

Part 3) $\frac{2}{3}$ ------> $(-\frac{10}{17}) / (-\frac{15}{17})$

Part 4) $3$ ------> $(2\frac{1}{4}) / (\frac{3}{4})$

Step-by-step explanation:

Part 1) we have

$2.75/(-2.2)$

To calculate the division problem convert the decimal number to fraction number

$2.75=275/100\\ -2.2=-22/10$

so

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Remember that

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(275/100)/(-22/10)=(275/100)*(-10/22)=-(275*10)/(22*100)=-(275)/(220)$

Simplify

Divide by 22 both numerator and denominator

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Part 2) we have

$(-2\frac{3}{5}) / (\frac{3}{5})$

To calculate the division problem convert the mixed number to an improper fraction

$(-2\frac{3}{5})=-\frac{2*5+3}{5}=-\frac{13}{5}$

so

$(-\frac{13}{5}) / (\frac{3}{5})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{13}{5}) / (\frac{3}{5})=(-\frac{13}{5})*(\frac{5}{3})=-\frac{13*5}{5*3}=-\frac{13}{3}$

Convert to mixed number

$-\frac{13}{3}=-(\frac{12}{3}+\frac{1}{3})=-4\frac{1}{3}$

Part 3) we have

$(-\frac{10}{17}) / (-\frac{15}{17})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{10}{17}) / (-\frac{15}{17})=(-\frac{10}{17})*(-\frac{17}{15})=\frac{10*17}{17*15}=\frac{10}{15}$

Simplify

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Part 4) we have

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To calculate the division problem convert the mixed number to an improper fraction

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so

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Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(\frac{9}{4}) / (\frac{3}{4})=(\frac{9}{4})*(\frac{4}{3})=\frac{9*4}{4*3}=\frac{9}{3}=3$

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