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3 years ago

What is the volume ,In cubic units ,of Anna’s figure ?

Mathematics

1 answer:

attashe74 [19]3 years ago

7 0

The first column has 10 cubes.

The question states that the other two columns each have 4 fewer cubes than the first column.

10 - 4 = 6

This means that each of the other 2 columns have 6 cubes each.

Column 1: 10 Cubic units

Column 2: 6 Cubic units

Column 3: 6 Cubic units

10 + 6 + 6 = 22

Anna’s Figure has 22 Cubic Units

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tigry1 [53]

<u>Answer:</u>

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

<u>Solution:</u>

Need to solve given equation using quadratic formula.

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General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

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Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

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