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Travka [436]
3 years ago
14

What is the volume ,In cubic units ,of Anna’s figure ?

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0

The first column has 10 cubes.

The question states that the other two columns each have 4 fewer cubes than the first column.

10 - 4 = 6

This means that each of the other 2 columns have 6 cubes each.

Column 1: 10 Cubic units

Column 2: 6 Cubic units

Column 3: 6 Cubic units

10 + 6 + 6 = 22

Anna’s Figure has 22 Cubic Units

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Answer:

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Check the picture please if you're good at math!!
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Answer:

A

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5 0
3 years ago
What is the answer and how did you work it out
Anna71 [15]

Answer: b

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8 0
4 years ago
Use the quadratic formula to solve the following equation -3x^2-x-3=0
tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

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3 years ago
Please help with this! You don't know how much you are helping me!
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If you want help on cheating download photomath its a calculator that takes a picture of what your doing and solves it with work
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