Answer:
Wonka bars=3 and Everlasting Gobstoppers=24
Step-by-step explanation:
let the wonka bars be X
and everlasting gobstoppers be Y
the objective is to
maximize 1.3x+3.2y=P
subject to constraints
natural sugar
4x+2y=60------1
sucrose
x+3y=75---------2
x>0, y>0
solving 1 and 2 simultaneously we have
4x+2y=60----1
x+3y=75------2
multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have
4x+2y=60
4x+12y=300
-0-10y=-240
10y=240
y=240/10
y=24
put y=24 in equation 2 we have'
x+3y=75
x+3(24)=75
x+72=75
x=75-72
x=3
put x=3 and y=24 in the objective function we have
maximize 1.3x+3.2y=P
1.3(3)+3.2(24)=P
3.9+76.8=P
80.7=P
P=$80.9
The answer is 6.25 square kilometres
one side is 1.25 and the other will be 1.25*4 =5
and for the area we multiply the two 1.25*5=6.25
Answer:
I think x = 1.5
Step-by-step explanation:
23 - 17 = 6
6 ÷ 4 = 1.5
Answer:
Step-by-step explanation:
y + 3 = 7(x - 1)
y + 3 = 7x - 7
y = 7x - 10
Answer:
1
Step-by-step explanation:
