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3 years ago

6. Chris can buy an online magazine

Mathematics

2 answers:

lakkis [162]3 years ago

7 0

Answer:

$6.88

Step-by-step explanation:

We are trying to compare two options: Buying a magazine for 12 months or for just 1 year.

To solve this, we can multiply the monthly rate by 12 because there are 12 months in a year.

5.99 x 12 = 71.88

The other option is to just pay $65 dollars for a whole year (12 months).

Comparing the two options, we see paying for the whole year is cheaper than paying for each month individually. Because of this, we can subtract $65, the cheaper option, from $71.88 to get $6.88

Chris will save $6.88 by paying for the whole year instead of purchasing for each month.

AlexFokin [52]3 years ago

7 0

Answer this by using system of equations. Say y=total money spent and x=number of years. y=5.99x and y=65
now set these equations equal to each other
5.99x=65
x=10.851419

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Is triangle MNL congruent to triangle QNL? Why or why not? Yes, they are congruent by either ASA or AAS. Yes, they are both righ

sergij07 [2.7K]

See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
==============================================
As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°

(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°

So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS

=======OR=======

So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA

=====================================
So, the correct answer is the first option

Yes, they are congruent by either ASA or AAS

3 0

3 years ago

Read 2 more answers

If the following two triangles are similar, find X. Show work please

anastassius [24]

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storchak [24]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

404 + 50 + 50 = 504

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