K= -3
3y = x+6 can be rewritten as y = 1/3x + 2
a perpendicular slope is the opposite reciprocal of the original slope
so instead of 1/3 it would be -3
therefore. k must equal -3 to be perpendicular to 3y = x+6
It all depends on the exact problem. Most hexagons have an interior of 60 degrees and an exterior of 120. Hope this helps!
Answer:
Using reflexive property (for side), and the transversals of the parallel lines, we can prove the two triangles are congruent.
Step-by-step explanation:
- Since AB and DC are parallel and AC is intersecting in the middle, you can make out two pairs of alternate interior angles<em>.</em> These angle pairs are congruent because of the alternate interior angles theorem. The two pairs of congruent angles are: ∠DAC ≅ ∠BCA, and ∠BAC ≅ ∠DCA.
- With the reflexive property, we know side AC ≅ AC.
- Using Angle-Side-Angle theorem, we can prove ΔABC ≅ ΔCDA.
Answer:
Simplifying the expression: 
we get 
Step-by-step explanation:
We need to simplify the expression:
First we will solve terms inside the bracket
Converting mixed fraction 
into improper fraction, we get: 
Replacing the term:
Now, taking LCM of: 5,3,4,2 we get 60
Now multiply 60 with each term inside the bracket
Now, combine like terms
Now, multiply all terms with 2
So, Simplifying the expression: we get
The correct answer is y= 0.513(1.833)^x
Explain
We will use the equation on this form
Y=ab^x
Let’s us plug in the coordinates of first point
(X, y) , ( 9, 120)
We will have
Y=ab^x
120= ab^9
Our equation for a will be
Ab^9 = 120
ab ^9 / b^9 = 120/ b^9
a = 120/ b^9
So will have
Y= 120/ b^9 • b^x
Then we will plug in coordinates for the second point
( x,y) = ( 10, 220)
We will have
Y= 120/b^9 • b^x
220 = 120/b^9 • b^10-9
220= 120b
Divide both side by 120
B= 11/6
B= 1.833333 = 1.833
Let’s plug in the value b=11/6 to our equation for a
A= 120/b^9
A= 120/ 11/6^9
A= 120/11^9/6^9
A=120 • 6^9 / 11^9
= 0.51285 which equal to 0.513
So therefore the answer is
Y= 0.513(1.833)^x
I hope this help you
:D
