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3 years ago

7

You see an emergency vehicle with audible and visible signals approaching from behind while you are stopped at an intersection.

What should you do?

1 answer:

Debora [2.8K]3 years ago

3 0

Pull over as fast as you can

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15pts-- multiple choice!

katrin2010 [14]

Answer: bonds
Explanation: will allow for a risk free option and to gain money from a little bit of time and money
(not 100% sure on answer but I believe it is bonds)

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3 years ago

Assume that product Alpha and product Beta are both priced at $1 per unit and that Ellie has $20 to spend on Alpha and Beta. She

alexira [117]

Answer:

D.

Explanation:

Marginal Utility puts a numerical value on the amount of satisfaction that a consumer gets from buying an additional unit of a product or service. Therefore based on this information it can be said that the information provided in the question indicates that in order to maximize utility, Ellie should buy more of Alpha and less of Beta, mainly due to the fact that the marginal cost of Alpha is double that of Beta and both cost the same price.

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3 years ago

Some hoodlums who have been earning money by stealing copper pipes and cable and selling them to recyclers are driving around on

icang [17]

Answer:

Yes they have

18 U.S. Code § 32 (a) Clause 3

Explanation:

With aviation being such a sensitive field that requires a lot of oversight, Congress enacted rules to punish aviation crimes which means that such crimes fall under Federal jurisdiction and as this crime is a crime against an aviation facility, it is a Federal crime.

The crime in question here falls under <em>US. Code 32 - Destruction of aircraft or aircraft facilities under subsection (a)3</em> which talks about damaging an air navigation facility and how this can endanger the safety of flights en route.

Their punishment would be either a fine, imprisonment of not more than five years or both.

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3 years ago

What is the best way to speed up time when only doing work

Anna35 [415]

acomodar la mercancia

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2 years ago

Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,

wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time = mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be $I_i$ :

$I_i = \dfrac{R^2}{\mu (\mu-R)}$

$I_i = \dfrac{2.1^2}{5 (5-2.1)}$

$I_i = \dfrac{4.41}{5 (2.9)}$

$I_i = \dfrac{4.41}{14.5}$

$\mathbf{I_i = 0.30}$

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

$\delta = \dfrac{R}{\mu}$

$\delta = \dfrac{2.1}{5}$

${\delta = 0.42}$

$\mathbf{\delta = 42}$

(c) The amount of time during an eight-hour day that the repairman is not out on a call is calculated as :

Percentage of Idle time = 1 - $\delta$

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58 × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0

4 years ago