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Ivan
3 years ago
5

BE is the midsegment of triangle ACD. The value of x is:

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0
The midsegment theorem says that the midsegment is half the third side and parallel as well. 20*2 is 40 so x = 35
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Andrej [43]

Answer:

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Step-by-step explanation:        

We have been given a triangle and we are asked to find the length of AC (b).

We will use law of cosines to find the length of side AC.

c^{2}=a^{2}+b^{2}-2ab \text{ cos }\theta

Upon substituting our given values in the formula we will get,

(AC)^{2}=15^{2}+12^{2}-2\times 15\times 12 \text{ cos}(106)  

(AC)^{2}=225+144-360\text{ cos}(106)      

(AC)^{2}=369-360(-0.275637355817)      

(AC)^{2}=369+99.22944809412    

(AC)^{2}=468.22944809412

Upon taking square root of both sides of our equation we will be get,

AC=\sqrt{468.22944809412}

AC=21.6386101238993629\approx 21.64  

Therefore, the length of b is 21.64 and option B is the correct choice.

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8 0
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Answer:

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Step-by-step explanation:

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3 years ago
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