Question

When Sharon begin shopping this morning, she have $40. she purchased 5 paperback books and had lunch. The books were all the same price and lunch cost $3.25 she now has $7 left over what was the price of each book
a. 8.75
b. 5.95
c.6.60
d.7.35

Answer 1

Call the price of a book 'b'. We know that lunch cost $3.25 so let's say $L=3.25$ we also know the total is $40. So we can write: 
$T=L+5b+7$
or
$40=3.25+5b+7$ 
and then solve for 'b':
$29.75=5b$
$b=\frac{29.75}{5} = 5.95$

A book cost $5.95