Would the answer be 36? It doesn't sound correct?

DIA [1.3K]

N is equal to 2.5

I divided 20 by 5 to get 4. = 20 ÷ 5 = 4. So, I divide 10 by 4 to get n. = 10 ÷ 4 = 2.5

Or we can do this solution.

20 5
---- = ---- ; do cross multiplication. 20n = 10(5)
10 n

20n = 50 ; to get n, divide both sides by 20. 20n / 20 = 50 / 20 = n = 2.50

Whichever way: 20/10 = 5/2.5

6 0

3 years ago

El seño Alonso pidió prestado dinero a una tasa del 8% anual . Si el cargo por interéses ese año es de $360 cuánto recibirá de p

natima [27]

Answer:

$ 4500

Step-by-step explanation:

Dejar;

Principal sea P

El tiempo sea T

Tasa sea R

Interés sea yo

De la pregunta;

R = 8%, T = 1 año, I = $ 360, P =?

De;

I = PRT / 100

100I = PRT

P = 100 I / RT

P = 100 * 360/8 * 1

P = $ 4500

5 0

3 years ago

How many parts are there in the format of a two-column proof? 3 4 5 6

GREYUIT [131]

Answer:

6

Step-by-step explanation:

8 0

3 years ago

If two triangles have three corresponding angles and three corresponding sides that are equal in measure, are the two triangles

nikitadnepr [17]

Yes, they are.

If the triangles have three corresponding angles equal means that they are either similar or congruent.

The definition of congruent means that the sides have the same length. That is precisely what the statement says.

So, being the lengths of the corresponding angles the same the two triangles are identical, this is they are congruent.

6 0

3 years ago

Read 2 more answers

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

3 years ago