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mafiozo [28]
3 years ago
8

37 pumpkins each weighs 48 ounces

Mathematics
1 answer:
KiRa [710]3 years ago
5 0
37 * 48 = 3 * (c  - 140 )+ 2 *(c  - 140 ) + ( c - 140 ) =>
37 * 48 = 6 * ( c - 140 ) =>
37 * 48 / 6 = c - 140 =>
37 * 8 = c - 140 =>
296 = c - 140 => 
c = 296 + 140 =>
c = 436 ounces.
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A PAIR OF JEANS MARKED AT R450 IS SOLD AT DISCOUNT OF 25%.​
Stolb23 [73]

Original price is the jeans = Rs450

Discount = 25%

Discount amount

= 25% of 450

= 25%(450)

= 25/100 × 450

= 25/10 × 45

= 5/2 × 45

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3 years ago
Please answerrrr Graph g(x), where f(x) = 4x − 2 and g(x) = f(x + 1). a line labeled g of x that passes through points 0, negati
Mrrafil [7]

Answer:

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

Step-by-step explanation:

we have

f(x)=4x-2

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To determine g(x), substitute the variable x by (x+1) in the function f(x)

so

f(x+1)=4(x+1)-2

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a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

4 0
3 years ago
Read 2 more answers
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

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so that

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One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

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Solve for <em>x</em> and <em>y</em>. We have

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==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

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