Answer:
The second one
The third one
Step-by-step explanation:
Answer:
93
Step-by-step explanation:
Key :
A1 = Algebra 1
A2 = Algebra 2
Alright so basically lets first look at the info they gave us :
We have 5 more than twice as many students taking A1 than we do A2.
We have 44 students taking A2.
And we need to find the least amount of students that could be taking A1.
So we need to take the amount of students taking A2 (44) and double it to find the amount taking A1.
So we can do 44 x 2 = 88 to get this.
But the problem also states there is 5 more then twice the number of students taking A2.
So we have that 88 but now we just need to add 5 to make up for them telling us that in the problem.
So :
88 + 5 = 93
Our final answer and least amount of students taking A1 is 93 students.
Answer:
ty = 53
Step-by-step explanation:
Given
= 
Cancel the z on the numerator/denominator of the left side and
Cancel the w on the numerator/denominator of the right side, leaving
= 
Cross- multiply
ty = tx ← tx = 53, hence
ty = 53
Answer:
In the picture above.
Step-by-step explanation:
Good luck.
Answer:
12.5 minutes
Step-by-step explanation:
Just divide 25 by 3 to get 12.5
