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uranmaximum [27]
3 years ago
10

If two fair dice are rolled what is the probability that the sum of the dice is 10, given the sum is greater than 4

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0
Sum is 10 = (4, 6), (5, 5), (6, 4) = 3
sum is greater than 4 = 30
<span>P(the sum of the dice is 10 | the sum is greater than 4) = 3/30 = 1/10</span>
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Find the slope of the line passing through the points (-2,3) a<br> and<br> (-9,6).
larisa [96]
<h3>Answer:   Slope = -3/7</h3>

===================================================

Apply the slope formula

m = (y2-y1)/(x2-x1)

m = (6-3)/(-9-(-2))

m = (6-3)/(-9+2)

m = 3/(-7)

m = -3/7

This means each time you go down 3 units, you go to the right 7 units.

Slope = rise/run = -3/7

rise = -3 and run = 7

7 0
3 years ago
2/8 is what as a decimal
Lilit [14]
2/8 is .25 as a decimal  .
8 0
3 years ago
Can somebody help me please ASAP first person to answer gets brainliest
sleet_krkn [62]

Answer:

Yes, d = 7, 32, 39, 46

Step-by-step explanation:

You can see each time it goes up by 7, meaning it is arithmetic.

The sequence would be: 4, 11, 18, 25, 32, 39, 46

8 0
3 years ago
In a trapezoid ABCD with legs AB and CD, the diagonals intersect each other at point O. Compare the areas of △ABO and △CDO.
atroni [7]

ar(ΔABO) = ar(ΔCDO)

Explanation:

The image attached below.

Given ABCD is a trapezoid with legs AB and CD.

AB and CD are non-parallel sides between the parallels AD and BC.

In ΔABD and ΔACD,

We know that, triangles lie between the same base and same parallels are equal in area.

⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.

Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)

Now consider ΔABO and ΔCDO,

Subtract ar(ΔAOD) on both sides of (1), we get

ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)

⇒ar(ΔABO) = ar(ΔCDO)

Hence, ar(ΔABO) = ar(ΔCDO).

4 0
3 years ago
PLEASEE HELPPPP IVE BEEN WAITING FOR HOURS!!!!!
kozerog [31]

Answer:

The perimeter is 32\sqrt{7} cm.

Step-by-step explanation:

Perimeter is found by adding all sides of the triangle together. So, this is what we need to find: 8\sqrt{7}+4\sqrt{63}+6\sqrt{28}

  • Only <u>like radicals</u> can be added or subtracted from one another. They'll have the same root number (which seems to be true for this question) as well as the radicand, which is the number/expression under the radical.

Look at the number under the radical: 7, 63, and 28. These numbers all share a factor of 7:        7/7 = 1,          63/7 = 9,         28/7 = 4.

Notice how 9 and 4 are perfect squares, so we can simplify the radicals using this common factor of 7.

8\sqrt{7} remains the same;    4\sqrt{63}=4\sqrt{9(7)} =4(3)\sqrt{7}=12\sqrt{7}; and

6\sqrt{28}=6\sqrt{4(7)}=6(2)\sqrt{7}=12\sqrt{7}. Now they are like radicals and can be added!

8\sqrt{7}+12\sqrt{7}+12\sqrt{7}=32\sqrt{7}

3 0
2 years ago
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