Question

In triangle ABC angle BAD is 46° find BCA and AB=AD=AC

Answer 1

Look at the picture.

$m\angle a=\dfrac{180^o-46^o}{2}=67^o\\\\m\angle b=180^o-67^o=113^o\\\\m\angle x=\dfrac{180^o-113^o}{2}=33.5^o\\\\Answer:\ [1]\ 33.5^o$