In triangle ABC angle BAD is 46° find BCA and AB=AD=AC

Mathematics

1 answer:

Shalnov [3]4 years ago

5 0

Look at the picture.

$m\angle a=\dfrac{180^o-46^o}{2}=67^o\\\\m\angle b=180^o-67^o=113^o\\\\m\angle x=\dfrac{180^o-113^o}{2}=33.5^o\\\\Answer:\ [1]\ 33.5^o$

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