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3 years ago

(3x^2a - 4y^a z^3a) ^2 ...?

1 answer:

8 0

The answer is 9x⁴ᵃ - 24x²ᵃyᵃz³ᵃ + 16 y²ᵃz⁶ᵃ

(a - b)² = a² - 2ab + b²
(3x²ᵃ - 4yᵃz³ᵃ)² = (3x²ᵃ)² - 2 * 3x²ᵃ * 4yᵃz³ᵃ + (4yᵃz³ᵃ)² =
= 3²x²ᵃ*² - 2 * 3 * 4 x²ᵃ * yᵃz³ᵃ + 4²yᵃ*²z³ᵃ*² =
= 9x⁴ᵃ - 24x²ᵃyᵃz³ᵃ + 16 y²ᵃz⁶ᵃ

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Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π

lorasvet [3.4K]

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The instantaneous rate of change at a given value of $x$ can be found by concept of derivative, which is described below:

$g(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Where $h$ is the difference rate.

In this question we must find an expression for the instantaneous rate of change of $g$ if $f(x) = \sin x$ and evaluate the resulting expression for $x = \frac{\pi}{3}$ . Then, we have the following procedure below:

$g(x) = \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin h}{h}\cdot \lim_{h \to 0} \cos x$

$g(x) = \cos x$

Now we evaluate $g(x)$ for $x = \frac{\pi}{3}$ :

$g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}$

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2. $\blacksquare$

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

4 0

2 years ago

Please help!!! (Look at photo)

Alexxx [7]

Answer:

330=40x+50

Step-by-step explanation:

then you would -50 from both sides

280=40x

then you would divide both sides by 40 to isolate x

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2 years ago

The graph below shows a line segment MN: graph of line MN going through ordered pairs negative 2, 3 and 1, negative 3 Which of t

Katyanochek1 [597]

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