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MariettaO [177]
2 years ago
6

What is the decimal equivalent to 15 1/4

Mathematics
2 answers:
kvasek [131]2 years ago
8 0
Answer: 15.25
1/4 is 0.25, so 15 + 0.25 is 15.25.
tankabanditka [31]2 years ago
4 0
I would say 15.25 is the answer
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What's the value of x and y?​
krok68 [10]

Answer:

x = 45 and y = 90

Step-by-step explanation:

Let the third angle be z

z = 180 - 135 (Linear Pair)

z = 45

Since its an iscosceles triangle,

<z = <x (angles opposite to equal sides have equal angles)

<x = 45 degree

<z + <x + <y = 180

45 + 45+ <y = 180

90 + <y = 180

<y = 180 - 90

<y = 90

Therefore x = 45 and y = 90

Hope u understood please mark as brainliest

Thank You

6 0
2 years ago
Read 2 more answers
Consider the next 1000 90% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on whi
Ivenika [448]

Answer:

90% CI expects to capture u 90% of time

(a) This means 0.9 * 1000 = 900 intervals will capture u

(b) Here we treat CI as binomial random variable, having probability 0.9 for success

n = 1000

p = 0.9

For this case, applying normal approximation to binomial, we get:

mean = n*p= 900

variance = n*p*(1-p) = 90

std dev = 9.4868

We want to Find : P(890 <= X <= 910) = P( 889.5 < X < 910.5) (integer continuity correction)

We convert to standard normal form, Z ~ N(0,1) by z1 = (x1 - u )/s

so z1 = (889.5 - 900 )/9.4868 = -1.11

so z2 = (910.5 - 900 )/9.4868 = 1.11

P( 889.5 < X < 910.5) = P(z1 < Z < z2) = P( Z < 1.11) - P(Z < -1.11)

= 0.8665 - 0.1335

= 0.733

6 0
3 years ago
What is the domain of -2
Free_Kalibri [48]
The answer is 7x so I this helps you please thank me plz bye
5 0
2 years ago
Dimetri says that a function that is made of terms where the variables is raised only to an odd power will be an odd function.Do
lana [24]

Here we want to study the relation between the exponents in a polynomial function and the "odd" property of functions.

We will see that Dimetri is correct.

-------------------------------

We start by defining an odd function as a function such that:

f(-x) = -f(x).

Now, let's see a simple function with only odd exponents.

f(x) = a*x  (the exponent is 1, so it is odd).

if we evaluate this in x = 1, we get:

f(1) = a

If we evaluate this in x = -1, we get:

f(-1) = a*-1 = -a

Then this is odd.

Now let's see a more general case and why Dimetri is correct.

For the rule of signs, when we multiply 2 negative numbers, the <u>product is positive.</u>

So always that we have an even exponent on a negative number, the outcome will be positive.

This does not happen for odd exponents, because we can't separate all the products in groups of 2, thus if we take the <u>odd exponent of a negative number, the outcome is negative</u>.

Then for functions with only odd exponents, the <u>outcome for evaluating the function in a given input is exactly the opposite of evaluating the same function with the opposite input</u>.

This means that the function is odd.

Again, note that this only happens if the function only has odd exponents.

If you want to learn more, you can read:

brainly.com/question/15775372

6 0
2 years ago
What is the solution set for the inequality 4−5g &gt; 39 Question 3 options: g &lt; −7 g&gt;7 g&lt;7 g &gt; −7.
neonofarm [45]

Answer:

g < -7

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

*Note:

When dividing or multiplying both sides of the inequality by a negative, <em>flip</em> the inequality sign.

<u>Step 1: Define</u>

<em>Identify.</em>

4 - 5g > 39

<u>Step 2: Solve for </u><u><em>g</em></u>

  1. [Subtraction Property of Equality] Subtract 4 on both sides:                    -5g > 35
  2. [Division Property of Equality] Divide -5 on both sides:                              g < -7

∴ any number <em>g</em> less than -7 would work as a solution to the inequality.

---

Topic: Algebra I

Unit: Inequalities

8 0
2 years ago
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