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Natalija [7]
3 years ago
5

hona is buying a rug for her room. Store A has the rug for $45 with a 10% discount. Store B has the same rug for $46 and is offe

ring a $10 rebate. The sales tax is 6% on either purchase. If Shona only has $40 to spend, which store will she purchase the rug from, and how much will she have left over?
Computers and Technology
1 answer:
Fed [463]3 years ago
7 0
Store b. This will have her paying 36.00 for the rug. Store A she will pay 40.50
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To conserve its public IP addresses, a company can instead use ____ addresses for devices within its own network boundaries.
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Create a class called Circle, which has (i) an attribute radius, (ii) a method that returns the current radius of a circle objec
nadya68 [22]

Answer:

Explanation:

The following class is written in Java. I created the entire Circle class with each of the methods and constructor as requested. I also created a tester class to create a circle object and call some of the methods. The output can be seen in the attached picture below for the tester class.

class Circle {

   double radius;

   public Circle(double radius) {

       this.radius = radius;

   }

   public double getRadius() {

       return radius;

   }

   public void resetRadius() {

       radius = 0;

   }

   public double calculateArea() {

       double square = Math.pow((Math.PI * radius), 2);

       return square;

   }

}

8 0
2 years ago
given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i &lt; j &lt; a.length), such that a[
Nimfa-mama [501]

Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

<em>// C++ program for the above approach</em>

<em> </em>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em> </em>

<em>// Function to find the count required pairs</em>

<em>void getPairs(int arr[], int N, int K)</em>

<em>{</em>

<em>    // Stores count of pairs</em>

<em>    int count = 0;</em>

<em> </em>

<em>    // Traverse the array</em>

<em>    for (int i = 0; i < N; i++) {</em>

<em> </em>

<em>        for (int j = i + 1; j < N; j++) {</em>

<em> </em>

<em>            // Check if the condition</em>

<em>            // is satisfied or not</em>

<em>            if (arr[i] > K * arr[j])</em>

<em>                count++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << count;</em>

<em>}</em>

<em> </em>

<em>// Driver Code</em>

<em>int main()</em>

<em>{</em>

<em>    int arr[] = { 5, 6, 2, 5 };</em>

<em>    int N = sizeof(arr) / sizeof(arr[0]);</em>

<em>    int K = 2;</em>

<em> </em>

<em>    // Function Call</em>

<em>    getPairs(arr, N, K);</em>

<em> </em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ4

4 0
1 year ago
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