Shari plans to bake cherry pies and sell them for $9.50 each how much pies dose she have to sell to make $100 profit

Which number can each term of the equation be multiplied by to eliminate the fractions before solving ? -3/4 m-1/2=2+1/4mA 2B 3C

bixtya [17]

The correct answer is C. 4.

Typically, we look to multiply by the bottom number (the denominator) in order to get fractions to cancel out. If we multiply 1/6 by 6, we get just 1, which is why we do it.

In this problem, you have two different denominators, 2 and 4. If you multiply them all by 2, the term -3/4m will still be a fraction.

-3/4m * 2 = -3/2m

As a result, we must try 4 instead. This causes all of them to cease being a fraction. Even the one with 2 as a denominator.

-1/2 * 4 = -2

7 0

3 years ago

Read 2 more answers

Please help! 10 points and brainlyist!!

yarga [219]

Answer:

1.80 in^3

1.0 fluid ounces^3

Step-by-step explanation:

volume of a cone = 1/3 πr²h

π = 3.14

r = 2.2 / 2 = 1.1

h = the value of h can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

1.8² = 1.1² + b²

3.24 = 1.21 + b²

3.24 - 1.21 = b²

2.03

b = √2.03 = 1.42

Volume = 1/3 x 3.14 x 1.21 x 1.42 = 1.80 in^3

1.80 x 0.554 = 1.0 fluid ounces^3

5 0

3 years ago

85001 round to the nearest ten thousand

sveticcg [70]

95000 Is rounded to the nearest ten thousands

7 0

4 years ago

Read 2 more answers

In 1742, Christian Goldbach conjectured that every even number greater than 2 can be written as the sum of two prime numbers. Ma

mezya [45]

The Goldbach's conjecture is true for each of the following even numbers.

(a) 19+5

(b) 43+7

(c) 83+3

(d) 139+5

(e) 199+11

(f) 257+7

<h3>What is Goldbach's conjecture?</h3>

One of the most well-known and enduring open questions in number theory and all of mathematics is Goldbach's conjecture. It says that the sum of two prime numbers is the even natural number higher than two.

<h3>According to the given information:</h3>

A. 24 can be expressed as:

24 = 19 + 5

B. 50 can be expressed as:

50 = 43 + 7

C. 86 can be expressed as:

86 = 83 + 3

D. 144 can be expressed as:

144 = 139 + 5

E. 210 can be expresses as:

210 = 199 + 11

F. 264 can be expresses as:

264 = 257 + 7

The Goldbach's conjecture is true for each of the following even numbers.

(a) 19+5

(b) 43+7

(c) 83+3

(d) 139+5

(e) 199+11

(f) 257+7

To know more about Goldbach's conjecture visit:

brainly.com/question/13193113

#SPJ4

I understand that the question you are looking for is:

In 1742, Christian Goldbach conjectured that every even number greater than 2 can be written as the sum of two prime numbers. Many mathematicians have tried to prove or disprove this conjecture without succeeding. Show that Goldbach’s conjecture is true for each of the following even numbers.

a. 24,

b. 50,

c. 86,

d. 144,

e. 210,

f. 264

7 0

2 years ago

3x-4y=0 2x+y=110 no solution

weeeeeb [17]

Answer:

(x, y) = (40, 30)

Step-by-step explanation:

A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.

__

An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:

y = 110 -2x . . . . . . subtract 2x from both sides

Using this in the first equation gives ...

3x -4(110 -2x) = 0 . . . . substitute for y

11x = 440 . . . . . . . . . simplify, add 440

x = 40 . . . . . . . . . . divide by 11

y = 110 -2(40) = 30

The solution is (x, y) = (40, 30).

5 0

2 years ago