<span>Highest point = 1406.25
Number of seconds = 9.375
We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375
So let's calculate the height at t = 9.375.
y = -16t^2 + 300t
y = -16(9.375)^2 + 300(9.375)
y = -16(87.890625) + 300(9.375)
y = -1406.25 + 2812.5
y = 1406.25
So the highest point will be 1406.25 after 9.375 seconds.
Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.'
y = -16t^2 + 300t
y = -16(9.375 + e)^2 + 300(9.375 + e)
y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e)
y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e
y = 1406.25 - 16e^2
Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
The answer to the question
Answer:
No I don't agree with their solution; both their answers are wrong.
Correct answer is
.
Step-by-step explanation:
Given:

Now given:
According to Mai
and According to Tyler 
Now we need to find which of them is correct.
So we will solve the given equation we get;

Subtracting both side by 1 we get;

Now Multiplying both side
we get;

Hence both of them are incorrect, correct answer is
.
Answer:
See Explanation
Step-by-step explanation:
Let us briefly explain the terms
- Variable: This is the letter in the expression
- Coefficient: This is the number beside the letter above
- Constant: This is a number without any variable attached.
Let us take our expression with two terms to be: 3x+5
Coefficient =3
Variable =x
Constant =5
The word phrase of the expression is:
5 added to the product of 3 and a number.