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3 years ago

9

a picture on the wall in Germany's classroom has 4 right angles 4 sides of equal length and 2 pairs of opposite sides that are p

arallel what quadrilateral best describes the picture

1 answer:

satela [25.4K]3 years ago

3 0

Hello!

I believe that a square best describes the picture. A square, as it mentions, has 4 equal right angles and 4 sides as well. A square also has 2 pairs of opposite sides that are parallel of each other.

I hope this helps!

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Evaluate 0.035×1.02/0.00015 leaving your answer in standard form

denis-greek [22]

0.035 x 1.02 is equal to 0.0357. 0.0357 divided by 0.00015 is equal to 238.

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Graph f(x)=8x^2+16x+3

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Answer:

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Step-by-step explanation:

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Add $50 million and 179.7 billion,

d1i1m1o1n [39]

50 million + 179.7 Billion = 179.75 billion.

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3 years ago

Read 2 more answers

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

Using the order of operation which should be done first to evaluate 6+(-5-7)/2-8(3)?

valentinak56 [21]

Answer:

$\frac{3}{11}$

Step-by-step explanation:

=> $\frac{6+(-5-7)}{2-8(3)}$

=> $\frac{6+(-12)}{2-24}$

=> $\frac{6-12}{-22}$

=> $\frac{-6}{-22}$

=> $\frac{3}{11}$

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3 years ago