A chord and a radius form an equilateral triangle.
The area of the larger segment is:
A = 5/6 r² π + r²√3/2 = 5/6 · 64 · 3.14 + 32 · 1.73 =
= 167.47 + 55.36 = 222.83 in²
Answer:
x=3
Step-by-step explanation:
Since T is the midpoint of SU, this means that ST is equivalent to TU.
-8.571428571428571 look up percentage calculator and do it
Answer:
mabe divided by 2
Step-by-step explanation: