Question

If 10g of sodium react with an unlimited amount of chlorine how much sodium chloride will get produced?

Answer 1

Answer: Amount of  sodium chloride produced is 25.43 grams.

Explanation:

To calculate the moles:

$\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}$

Given: Mass of sodium = 10 g

Molar mass of sodium = 23g/mol

$\text{Moles of sodium}=\frac{10g}{23g/mol}=0.4347mol$

The balanced equation is:

$2Na+Cl_2\rightarrow 2NaCl$

By Stoichiometry of the reaction,

2 moles of sodium produces 2 moles of sodium chloride

So, 0.4347 moles of sodium will produce =$\frac{2}{2}\times 0.4347=0.4347mol$ of sodium chloride.

Molar mass of sodium chloride = 58.5 g/mol

Putting values in equation 1, we get:

$0.4347mol=\frac{\text{Mass of NaCl}}{58.5g/mol}=25.43g$

Hence, amount of sodium chloride produced is 25.43 grams.