If the mean score on a stress test is 5, the standard deviation is 2, and the distribution is normal, what would be the mean val

Question

3 years ago

15

ue when converted to a z distribution

1 answer:

expeople1 [14] · Answer 1 · 2022-02-13T20:07:20+03:00

Answer: 0

Step-by-step explanation:

Given that :

Mean score on test = 5

Standard deviation on test = 2

Distribution = normal

The mean value when Converted to a z - distribution :

Zscore = (x - mean) / standard deviation.

Hence z score for the mean score will be :

X = mean score

Zscore = ( 5 - 5) / 2

Zscore = 0 / 2

Zscore = 0

Mean value when Converted to a z distribution will be 0