If the mean score on a stress test is 5, the standard deviation is 2, and the distribution is normal, what would be the mean val
ue when converted to a z distribution
1 answer:
Answer: 0
Step-by-step explanation:
Given that :
Mean score on test = 5
Standard deviation on test = 2
Distribution = normal
The mean value when Converted to a z - distribution :
Zscore = (x - mean) / standard deviation.
Hence z score for the mean score will be :
X = mean score
Zscore = ( 5 - 5) / 2
Zscore = 0 / 2
Zscore = 0
Mean value when Converted to a z distribution will be 0
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