Answer:
probability that Shaun loses both games
Step-by-step explanation:
Games are independent, so we find each separate probability, and multiply them.
In a chess club the probability that Shaun will beat Mike is 3/8.
So
probability that Shaun loses.
The probability that Shaun will beat Tim is 5/7 .
So
probability that Shaun loses.
What is the probability that Shaun loses both games?
This is:

probability that Shaun loses both games
Answer:4^2 or (-4)^2
Step-by-step explanation:
I don't really know how to explain it. I can try if you want
Answer:
The correct answer is actually around 21%. Are you sure the question wasn't asking what the approximate percent decrease from 85 to 70 was? Because in that case it would be around 17%.
Step-by-step explanation:
-11/2
Multiply 5 and 2, then add 1
-11/2, Hope this helps!