It looks like 4 i think so
Answer:
![x - (-8) = 3](https://tex.z-dn.net/?f=x%20-%20%28-8%29%20%3D%203)
![x = -5](https://tex.z-dn.net/?f=x%20%3D%20-5)
Step-by-step explanation:
Equation
![x - -8 = 3](https://tex.z-dn.net/?f=x%20-%20-8%20%3D%203)
Solving (a): Using Parenthesis
The equation can be rewritten by putting -8 in a parenthesis as follows;
![x - (-8) = 3](https://tex.z-dn.net/?f=x%20-%20%28-8%29%20%3D%203)
Solving (b): The correct answer
![x - (-8) = 3](https://tex.z-dn.net/?f=x%20-%20%28-8%29%20%3D%203)
Start by opening the bracket
![x + 8 = 3](https://tex.z-dn.net/?f=x%20%2B%208%20%3D%203)
Subtract 8 from both sides
![x + 8 - 8 = 3 - 8](https://tex.z-dn.net/?f=x%20%2B%208%20-%208%20%3D%203%20-%208)
![x = 3 - 8](https://tex.z-dn.net/?f=x%20%20%3D%203%20-%208)
![x = -5](https://tex.z-dn.net/?f=x%20%3D%20-5)
<em>Hence, the correct solution is </em>
<em></em>
<span>According to the Pythagoras's theorem, The sum of the square of the hypotenuse is equal to the sum of the square of the other two sides.
</span><span>x^2 + x^2 = (29)^2 = 29 x 29 = 281
2x^2 = 841
x^2 = 841/2 = 420.5
x = sqrt(420.5) = 20.51 inches</span><span>
</span>
Any fraction with a denominator of ' 1 ' is a unit rate.
" 0.05 thing per minute " is a unit rate.
Its reciprocal is another unit rate: " 20 minutes per thing ".
Answer:
The equation of the required line is: 2x + y = 8
Step-by-step explanation:
When a point on the line and the slope of the line are given, we use the slope - one - point form to determine the equation of the line.
Say,
is the point passing through the line and the slope of the line is say,
. Then the equation would be:
![$ (y - y_1) = m(x - x_1) $](https://tex.z-dn.net/?f=%24%20%28y%20-%20y_1%29%20%3D%20m%28x%20-%20x_1%29%20%24)
Here
and slope,
.
Therefore, the equation of the line becomes:
![$ y - (-6) = -2(x - 7) $](https://tex.z-dn.net/?f=%24%20y%20-%20%28-6%29%20%3D%20-2%28x%20-%207%29%20%24)
![$ \implies y + 6 = -2x + 14 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20y%20%2B%206%20%3D%20-2x%20%2B%2014%20%24)
Rearranging we get:
which is the required equation of the line.