I believe it is the second one hope that helped
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
Squaring a number means you're multiplying the number by itself. This would mean (6b)^2 = (6b)(6b).
I think it's true. I'm so sorry if it's wrong
The answer is BC = 38.22 cm.
<u>Step-by-step explanation</u>:
We have, ∠BKD = 120° ,BK = 28 cm, Draw a perpendicular from point K on BC let it intersect at point M. In right angled ΔBMK, ∠BKM=30° and BK = 28 cm
sin30° = perpendicular/hypotenuse
1/2 = BM/BK
1/2 = BM/28
BM= 14 cm
Now , In right angled ΔBMK ,
cos30° = base/hypotenuse
√3/2 = MK/28
MK = 14√3 = 24.22 cm
KMCD is a square MK = MC = 24.22 cm
also, BC = BM + MC , putting values of BM & MC we get :
BC = 14 cm + 24.22 cm
BC = 38.22 cm.
