All categories

2 years ago

What is the equation of the parabola in vertex form. Vertex(4,4),point(2,-4)

Mathematics

1 answer:

Ksju [112]2 years ago

6 0

Answer:

y = -2(x - 4)^2 + 4.

Step-by-step explanation:

Vertex form:

y = a(x - 4)^2 + 4 (because the vertex is at (4, 4)).

To find the value of a we substitute the point (2, -4):

-4 = a(2-4)^2 + 4

4a = -8

a = -2.

You might be interested in

A map has a scale of 1 in. : 38 ft use the given map distance to find the actual distance

Dvinal [7]

Answer:

for q 19 its x=209ft and for 21 its 66.5 ft i forgot q 20

Step-by-step explanation:

8 0

2 years ago

I need help on this one

Dominik [7]

Answer:

5.9625

Step-by-step explanation:

6 0

2 years ago

60% OFF!<br> Shannon wants to buy a rug. The original price is $70. What is the sale price?<br> $

Alexus [3.1K]

The sale price is $42. 70 x 0.60

3 0

2 years ago

Read 2 more answers

Problem 5. A skating rink in the shape shown has an area of

nexus9112 [7]

Answer:

$P=\dfrac{\pi r^2+2800}{r} $ ft$

Step-by-step explanation:

Let the length of the rectangular part =l

The width will be equal to the diameter of the semicircles.

Area of the Skating Rink= $2(\frac{\pi r^2}{2})+(lX2r)$

Therefore:

$\pi r^2+2lr=2800\\2lr=2800-\pi r^2\\$Divide both sides by 2r\\l=\dfrac{2800-\pi r^2}{2r}$

Perimeter of the Shape =Perimeter of two Semicircles + 2l

$=2\pi r+2\left(\dfrac{2800-\pi r^2}{2r}\right)\\=2\pi r+\dfrac{2800-\pi r^2}{r}\\=\dfrac{2\pi r^2+2800-\pi r^2}{r}\\=\dfrac{\pi r^2+2800}{r}$

The perimeter of the rink is given as:

$P=\dfrac{\pi r^2+2800}{r} $ ft$

4 0

2 years ago

누구든지 나를 도울 수 있을까요?

yKpoI14uk [10]

Answer:

The expanded form of 1.2*10^9 is 1400000000

I'm not very sure what you mean but I have found two solutions.

Solution No.1:

1400000000 - 7000 = 1399993000

Solution No.2:

Let's say the variable is "x"

7000 * x = 1400000000

x = 200000

Hope this helped! :)

4 0

2 years ago